Really need help!!! quadratic equations UGH

2 answers:

5 0

2m³ + 10 m = 48

2m² + 10m - 48 = 0, solve this quadratic for m. Apply the formula:

m'=[-b + √(b²+4ac)]/2a and m" ==[-b - √(b²+4ac)]/2a

WHERE a = 2, b=10, c= - 48
and you will find :
m= 3 and m= - 8 (answer a)

kati45 [8]3 years ago

4 0

$2m^2 + 10m = 48\\
2m^2+10m-48=0\\
m^2+5m-24=0\\
m^2-3m+8m-24=0\\
m(m-3)+8(m-3)=0\\(m+8)(m-3)=0\\
m=-8 \vee m=3$

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Show all work and provide necessary descriptions

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We can solve this expression for the coordinates of Q:

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Plug in the values for the coordinates of M and P to get

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horsena [70]

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It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.

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Learn more about the right angle triangle here:

brainly.com/question/3770177

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