Answer:
x= -3
y= -2
From the first one, if you add 2y to both sides you can plug that into the second one and solve for y. Then, plug y to the first one and solve for x.
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3
Answer:
no clue
Step-by-step explanation:
!!!!!!!!!!!
Answer:
reggie made an error
the correct scale factor is 2/3
Step-by-step explanation:
we want to get from A to A', B to B', and ultimately C to C'
to get there, we must multiply each value in each point by the scale factor.
let's start out with reggie's scale factor. he multiplies each value in C by 3/2 to get to C'. we can try this out with one point, e.g. A
for A: 3/2 * (-12, -6) = (-18, -9). this is not A' = (-8, -4)! thus, 3/2 cannot be the scale factor
now, onto hillary's scale factor of 2/3
for A: 2/3 * (-12, -6) = (-8, -4). this is A'! thus, hillary is correct and reggie made an error
the correct scale factor is thus hillary's: 2/3