Answer : The mass of water produced will be 32.78 grams.
Explanation : Given,
Mass of
= 21.9 g
Molar mass of
= 72.15 g/mole
Molar mass of
= 18 g/mole
First we have to calculate the moles of
.
![\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DC_5H_%7B12%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DC_5H_%7B12%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DC_5H_%7B12%7D%7D%3D%5Cfrac%7B21.9g%7D%7B72.15g%2Fmole%7D%3D0.3035moles)
Now we have to calculate the moles of
.
The balanced chemical reaction will be,
![C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)](https://tex.z-dn.net/?f=C_5H_%7B12%7D%28l%29%2B8O_2%28g%29%5Crightarrow%205CO_2%28g%29%2B6H_2O%28l%29)
From the balanced reaction we conclude that
As, 1 mole of
react to give 6 moles of ![H_2O](https://tex.z-dn.net/?f=H_2O)
So, 0.3035 moles of
react to give
moles of ![H_2O](https://tex.z-dn.net/?f=H_2O)
Now we have to calculate the mass of
.
![\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DH_2O%3D%5Ctext%7BMoles%20of%20%7DH_2O%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DH_2O)
![\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DH_2O%3D%281.821mole%29%5Ctimes%20%2818g%2Fmole%29%3D32.78g)
Therefore, the mass of water produced will be 32.78 grams.