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Crazy boy [7]
3 years ago
15

Enter an equation for the precipitation reaction that occurs (if any) when solutions of potassium hydroxide and nickel(ii) bromi

de are mixed. express you answer as a chemical equation including phases.
Chemistry
2 answers:
tester [92]3 years ago
6 0
The possible equation for the reaction that occurs when potassium hydroxide and nickel(II) bromide solutions are mixed was 2 KOH(aq)+NiBr₂(aq) → Ni(OH)₂(s)+2 KBr(aq).
The equation of the reaction between potassium hydroxide and nickel(II) bromide solutions when this two chemical are mixed are 2 KOH(aq)+NiBr₂(aq) → Ni(OH)₂(s)+2 KBr(aq).
Artemon [7]3 years ago
3 0

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Precipitation reaction is defined as the reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium hydroxide and nickel (II) bromide follows:

2KOH(aq.)+NiBr_2(aq.)\rightarrow Ni(OH)_2(s)+2KBr(aq.)

By Stoichiometry of the reaction:

2 moles of aqueous solution of potassium bromide reacts with 1 mole of nickel (II) bromide to produce 1 mole of solid nickel (II) hydroxide and 2 moles of potassium bromide

Hence, the chemical equation is written above.

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What is the result of crystals boiling the impure product with too much solvent and then cooling on ice?
VMariaS [17]

Answer: Option (c) is the correct answer.

Explanation:

It is known that when we tend to dilute an impure product with too much of solvent then it will lead to dissolution of the solute. As a result, the chances of formation of crystal reduces.

And, when we increase the temperature then there will occur increase in the number of collisions between the solute and solvent molecules.

Hence, solubility of the solute also increases with increase in temperature,  placing it on ice bath will further reduce the crystal formation, hence no crystal should be formed in the reaction.

Thus, we can conclude that the result of crystals boiling the impure product with too much solvent and then cooling on ice is that no crystals are produced.

8 0
2 years ago
Which of the following properties of a protein is least likely to be affected by changes in pH? Tertiary structure Primary struc
chubhunter [2.5K]

Answer:

Primary structure is the correct answer.

Explanation:

  • The primary structure is the simple level of protein structure.
  • Primary structure is a basic amino acids sequences in a protein.
  • In the primary structure, amino acids are attached together by a covalent bond.
  • Primary structure is when the amino acids are joined together with peptide bonds to produce polypeptide chains
  • Changes in pH are least likely to change the amino acid sequence or disrupt peptide bonds.

Explanation:

7 0
3 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
zaharov [31]
The equation for energy of a photon is E=hv where v equals frequency and h equals the Planck constant (6.626X10^-34). So since you've been given frequency you can just plug in frequency to find the total energy in joules.

E=(3.55X10^17)(6.626X10^-34)
E=2.35223X10^-16

Not sure how many significant figures you needed. Hope this helped.


4 0
3 years ago
What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
5 0
3 years ago
A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
givi [52]

Answer:

\mathbf{0.02 M}

Explanation:

\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

V_{EDTA} = 25 \ mL

V_{V^{+3}} = 59.0 \ mL

V_{Ga^{+3}} = 13.0 \ mL

M_{EDTA} = 0.0680 \ M

M_{V^{+3}} = ???(unknown)

M_{Ga^{+3}} = 0.0400 \ M

V^{+3} + EDTA \to V[EDTA] + EDTA(Excess)  \to^{CoA} \ Ga[EDTA] _{complex}

M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18

x = \dfrac{1.18}{59}

\mathbf{x =0.02 \ M }

5 0
3 years ago
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