Answer:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
Explanation:
Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
First, we will balance carbon and hydrogen which are in just one compound on each side.
C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
Finally, we will balance the oxygen atoms.
C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
In order to have integers, we will multiply everý compound by 2.
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
