Hello!
Ok so for this problem we use the ideal gas law of PV=nRT and I take it that the scientist needs to store 0.400 moles of gas and not miles.
So if we have
n=0.400mol
V=0.200L
T= 23degC= 273k+23c=296k
R=ideal gas constant= 0.0821 L*atm/mol*k
So now we rearrange equation for pressure(P)
P=nRT/V
P=((0.400mol)*(0.0821 L*atm/mol*k)*(296k))/(0.200L) = 48.6 atm of pressure
Hope this helps you understand the concept and how to solve yourself in the future!! Any questions, please feel free to ask!! Thank you kindly!!!
Answer:
thay all are different from each other
We are tasked to find the amount of O2 in grams given only the number of moles of oxygen gas. To solve the problem, we need first to calculate the molecular weight of oxygen. Based on the periodic table, elemental oxygen has a molecular weight of 16 g/mol. Thus its molecular weight is,
O2=16.0g/mol (2)=32 g/mol
To solve for the amount of compound oxygen in grams, we have,
O2 (g)=5 mol x 32 g/mol =160 g.
This cancel out the mols both in the numerator and denominator leaving only the g as a unit. Therefore, 5 mols of oxygen is equal to 160 g of oxygen.
Would it be standard notation
