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BlackZzzverrR [31]
3 years ago
12

HURRY WHICH ONE IS IT??

Chemistry
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

Protons are positive, electrons are negative, neutrons have to charge. Most of an Atoms mass comes from its protons and neutrons

Explanation:

I took some notes in my notebook about Atoms.

vichka [17]3 years ago
5 0
What sean said ^^^ ya yaayayayaya
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Can someone pls help me with this pls
Slav-nsk [51]

Answer:

I would say element

Explanation:

because it is made of two different types of atoms chemically bonded together!

I'm sorry if wrong!

8 0
3 years ago
A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
3 years ago
What might cause scientists to change a scientific theory?
ioda

Answer:

c

Explanation:

4 0
3 years ago
Read 2 more answers
The equation that describes the process of photosynthesis
Alexandra [31]
The last choice is the equation for photosynthesis
7 0
3 years ago
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Diameter 28cm,pie22/7find the circumference​
lutik1710 [3]

Answer:

88

Explanation:

2πr

radius=14/2=7

2×22\7*7=88

5 0
3 years ago
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