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Anna [14]
3 years ago
13

. ¿Qué cantidad de HNO3 concentrado y de solvente se utilizará en la preparación de 500 mLal 5% (v/v)?

Chemistry
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

464.29mL de solvente y 35.71mL de ácido nítrico concentrado deben agregarse.

Explanation:

El ácido nítrico concentrado viene al 70% v/v por temas de estabilidad. El volumen de ácido nítrico que se debe agregar si se quieren hace 500mL al 5% de HNO3 es:

500mL * (5mL / 100mL) = 25mL de ácido nítrico se deben agregar.

Como el ácido nítrico está al 70%:

25mL ácido nítrico * (100mL / 70mL ácido nítrico) = 35.71mL de ácido nítrico concentrado deben agregarse.

Y el volumen de solvente debe ser:

500mL - 35.71mL = 464.29mL

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Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m
nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0
3 years ago
PLEASE HELP ME ASAPPP!?
Brrunno [24]

lets guess and say #4???

7 0
3 years ago
When 3-iodo-3-ethylpentane is heated in methanol, the major organic product is an __________________ that is generated through a
katovenus [111]

Answer:

Ether

SN1 mechanism

Explanation:

The nucleophile in this reaction is CH3OH. It is a poor nucleopile. We already know that a poor nucleophile reacting with a tertiary alkyl halide often leads to the substitution product as the major product.

Also, the iodide ion is a good leaving group. This makes the SN1 substitution more likely yielding the ether as the major product as shown in the image attached.

5 0
3 years ago
The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect
DedPeter [7]

Answer: The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect of adding more bromine gas to the reaction chamber?

More fluorine gas will be produced.

More bromine gas will be produced.

More bromine monofluoride gas will be produced.

Less bromine monofluoride gas will be produced.

I think it is more bromine monofluoride will be produce

Explanation:

8 0
2 years ago
What mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane? (molar mass of ccl4 = 153.81 g/mol and molar m
natka813 [3]

4.42 g mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane.

It's easy to find the molecular mass of a compound with these steps: Determine the molecular formula of the molecule. Use the periodic table to determine the atomic mass of each element in the molecule. Multiply each element's atomic mass by the number of atoms of that element in the molecule.

The molar mass of any compound can be found out by adding the relative atomic masses of each element present in that particular compound.

Hexane is an organic compound, a straight-chain alkane with six carbon atoms and has the molecular formula C₆H₁₄.

Therefore,

⇒ 0.115 g of Hexane x (0.25 mol CCl4/1 mol hexane) x (153.81 g of CCl4/1 mol CCl4) = 4.42g CCl4.

To learn more about CCL4 and Hexane here

brainly.com/question/15156642

#SPJ4

7 0
2 years ago
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