Answer:
   256
Step-by-step explanation:
A calculator works well for this.
_____
None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.
1 to any power is still 1, so the factors (1^n) can be ignored.
After you ignore all of the things that can be ignored, your problem simplifies to ...
   (2^2)(2^-3)^-2
The rules of exponents applicable to this are ...
   (a^b)^c = a^(b·c)
   (a^b)(a^c) = a^(b+c)
Then your product simplifies to ...
   (2^2)(2^((-3)(-2)) = (2^2)(2^6) 
   = 2^(2+6) 
   = 2^8 = 256
 
        
             
        
        
        
False.
Only log(x^2)=2log(x)
For example, let x=10
(log(10))^2=1^2=1
yet 2log(10)=2*1=2
        
             
        
        
        
What is the situation from the problem
        
             
        
        
        
Answer: 64%
Step-by-step explanation:
You would divide 50 by 32 (32/50), and get the decimal 0.64. Multiply 0.64 by 100 and you will get 64, your percent.
 
        
             
        
        
        
Answer:
I don't know what, I would like to know