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3 years ago

What is the perimeter of the image attached?? (PLEASE HELP I WILL MARK BRAINLIEST)

Mathematics

1 answer:

Kitty [74]3 years ago

8 0

Answer:

$Perimeter = 3x + 3$

Step-by-step explanation:

Perimeter of the given triangle in the figure is the sum of all three sides.

The expressions for the 3 sides are given as, $x, (x - 3), (x + 6)$ .

Therefore,

$Perimeter = x + (x - 3) + (x + 6)$

Simplify,

$Perimeter = x + x - 3 + x + 6$

Collect like terms

$Perimeter = x + x + x - 3 + 6$

$Perimeter = 3x + 3$

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What is 10 1/4 - 2 2/4

lana66690 [7]

Answer:

10 1/4 - 2 2/4 = 37/4

Step-by-step explanation:

10 1/4 - 2 1/2
10*4+1/4 = 41/4
(41/4) - 1 = 37/4

That answer!

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3 years ago

What is the value of c?

GaryK [48]

Answer:

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3 years ago

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Firlakuza [10]

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2 years ago

Read 2 more answers

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

What is the varible of -10 = xy +z for x

Verdich [7]

The variable is y

Z is a constant.

4 0

3 years ago