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3 years ago

What is the perimeter of the image attached?? (PLEASE HELP I WILL MARK BRAINLIEST)

Mathematics

1 answer:

Kitty [74]3 years ago

8 0

Answer:

$Perimeter = 3x + 3$

Step-by-step explanation:

Perimeter of the given triangle in the figure is the sum of all three sides.

The expressions for the 3 sides are given as, $x, (x - 3), (x + 6)$ .

Therefore,

$Perimeter = x + (x - 3) + (x + 6)$

Simplify,

$Perimeter = x + x - 3 + x + 6$

Collect like terms

$Perimeter = x + x + x - 3 + 6$

$Perimeter = 3x + 3$

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Simplify the expression.

astra-53 [7]

$a^{\log_a b}=b\\\\12^{\log_{12}24}=24$

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3 years ago

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In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.

djyliett [7]

Answer:68.2

Step-by-step explanation:

cos6=71/EF

cos6= 0.960170286650366

0.960170286650366= 71/EF

0.960170286650366*71=EF

EF= 68.2

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3 years ago

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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 11 feet and

Inessa [10]

Answer: The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

where r is the length of its radius

* In container A:

∵ r = 13 feet , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

is complete, divide the volume of water left in container A

by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

8 0

3 years ago

I dont understand this

Mkey [24]

Answer:

a²+b²=c²

14²+10²=c²

196+100=c²

296=c²

√296=√c²

√296=c

I hope this helps:

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3 years ago

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You have been invited to be part of the planning committee for the County Fair. In order to be an effective member you will need

kakasveta [241]

Firstly let's find the dimension of this large rectangle:(given)

Area of Rectangle = 660 x 66 =43,560 ft²

And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²

We know that the 20 acres form a rectangle. We need to know what is their disposition:

1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS

Note that W=66 & L=666 = 43,956 ft²/ unit )

lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or

2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)

3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.

4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly

5 0

3 years ago