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lana [24]
4 years ago
12

The museum gives tours to students in groups of 7.Four fifth grade classes are going to the museum.There are 20 students in each

class,but 3 students were absent today.The museum needs to determine the number of your groups.Select true or False for each statement.
The expression (5×20-3)÷7 can be used to find the number of groups.True or False

The expression (4×20-3)÷7 can be used to find the number of groups. True or False

There will be 11 tour groups. True or False

There will be 77 tour groups. True or False
Mathematics
1 answer:
Alex73 [517]4 years ago
6 0
The expression (5×20-3)÷7 can be used to find the number of groups.
False

The expression (4×20-3)÷7 can be used to find the number of groups.
True

There will be 11 tour groups.
True

There will be 77 tour groups.
False

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4 years ago
What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7
cestrela7 [59]

Answer:

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

Step-by-step explanation:

We need to find the solution for x in the given equation.

\sqrt{9x+7} +\sqrt{2x}=7

Solving:

Subtract \sqrt{2x} from both sides

\sqrt{9x+7} =7-\sqrt{2x}

Taking square on both sides

(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation  \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764

Putting values and solving

x=\frac{-(-980)\pm\sqrt{(-980)^2-4(49)(1760)}}{2(49)}\\x=\frac{980\pm\sqrt{614656}}{98}\\Solving\\x=18 \,\, and x =2

Verifying the solution by putting values of x in given equation

Putting x=18

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(18)+7} +\sqrt{2(18)}=7\\\sqrt{169} +\sqrt{36}=7\\13+6=7\\19\neq 7

So, x=18 is not solution o given equation.

Putting x = 2

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(2)+7} +\sqrt{2(2)}=7\\\sqrt{25} +\sqrt{4}=7\\5+2=7\\7=7

So, x=2 satisfies the equation

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

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