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RideAnS [48]
3 years ago
6

Two walls are 26ft long by 9 9ft wide the other wall is 18ft long by 9ft wide. Each gallon of paint covers about 250sq ft how ma

ny gallon of paint should amelia buy to paint the walls?
Mathematics
1 answer:
Wittaler [7]3 years ago
7 0
Well u find the areas of both walls by using
Area= Length×Width
26×9=234
18×9=162
add the areas
162+234=396
then divide by 250
396÷250=1.584
since u can’t get 1.584 of a gallon of paint, the answer is 2
 
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Nata [24]

a). 0.45 with a line over the 45 means 0.45454545454545... forever.

It's equivalent to  45/99  which is  <em>5/11</em> .

b). 0.45 with a line over the 5 means 0.455555555... forever.

It's equivalent to (0.4 + 0.555555.../10)

The 0.4 part is  4/10

The 0.5555555555.../10 part is  5/90 .

(4/10) + (5/90) = <em>41/90 </em>

c). 0.45 means 45/100 .  That's <em> 9/20</em> .

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3 years ago
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Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

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{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

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aleksandr82 [10.1K]

Sam is using an industrial kitchen to make several batches of his famous chocolate chip granola bars. He needs to weight out 78 ounces of chocolate chips, plus or minus 2.5 ounces. The equation that can be used to find the minimum or maximum amount,c, of chocolate chips that he can weigh out is-

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