![\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20-7x-2y%3D4%5Cimplies%20-2y%3D7x%2B4%5Cimplies%20y%3D%5Ccfrac%7B7x%2B4%7D%7B-2%7D%5Cimplies%20y%3D%5Ccfrac%7B7x%7D%7B-2%7D%2B%5Ccfrac%7B4%7D%7B-2%7D%20%5C%5C%5C%5C%5C%5C%20y%3D%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B7%7D%7B2%7D%7D%20x-2%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.
Answer:2
because it is a 45 45 90
Step-by-step explanation:
1. the graph of 2x + 1 = y for all real numbers will be a line. the graph with the restricted domain will be a line segment meaning it has endpoints (1, 3) and (4, 9).
2. is open ended, meaning you can make A, B, C anything you want as long as what they specify is met.
(a) A = 0
(0)x + By = C
let's make B = 1 and C = 5
y = 5
(b) B = 0
Ax + (0)y = C
let's make A = 1 and C = 5
x = 5
(c) C = 0
Ax + By = 0
let's make both A and B = 1
x + y = 0
3. plot both intercepts (x on x-axis, y on y-axis) then draw a line through the dots.
4-7. linear equations do not have exponents on any of the variables. 1/y is the same as y^(-1) so both 4 and 7 are non-linear.
8-13. you will have to graph these. put them in slope intercept form: y = mx+b if they're not already , plot the y-intercept first (0, b) then use the slope m draw the line by going rise over run.
example 13.
3x + 4y = 12
4y = -3x + 12
y = (-3/4) + 3
plot (0,3)
go down -3 , right 4 make a point.
reverse from (0,3) go up 3 left -4 and make a point. connect with line.
Let's solve your equation step-by-step.
3x−5x+14=26
Step 1: Simplify both sides of the equation.
3x−5x+14=26
3x+−5x+14=26
(3x+−5x)+(14)=26(Combine Like Terms)
−2x+14=26
−2x+14=26
Step 2: Subtract 14 from both sides.
−2x+14−14=26−14
−2x=12
Step 3: Divide both sides by -2.
−2x
−2
=
12
−2
x=−6
Answer:
x=−6
You need the geometric means for right triangles. There are 3 different forms of it that help us solve for either leg, or the altitude. We are looking for how the altitude is related to the hypotenuse that is split in 2. For us that will look like this: 
. Your answer is "s", second choice down.
