Answer:
vjbsvjbavljjvldbsef
Step-by-step explanation:
Answer:
Interquartile range IQR = 5.5
Step-by-step explanation:
Interquartile range IQR = third quartile Q3 - first quartile Q1
IQR = Q3 - Q1 ........1
arranging the data in ascending order;
1,3,5,6,6,7,8,11,12
The median of the data is the 5th number which is 6
Separating the data into two halves;
(1,3,5,6,),6,(7,8,11,12)
The first quartile Q1 is; (the median of the first half)
Q1 = (3+5)/2 = 4
The third quartile Q3 is; (the median of the second half)
Q3 = (8+11)/2 = 9.5
The interquartile range IQR can be derived using equation 1;
IQR = Q3 - Q1 = 9.5 - 4
IQR = 5.5
Answer:
B - 87/100
Hope this helps, if I got it wrong I’m sorry
35+25=60
y=60
If you add the opposite side values of the triangle (not the one touching the y), you get the value of y). 35+25=y
This works because y+x= 180 and the three angles of a triangle add to 180.
