1. What are the coordinates of the circumcenter of a triangle with vertices A(0,1), B(2, 1) , and C(2, 5) ?
1 answer:
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Answer:
17.32m ; 110°
Step-by-step explanation:
Distance between X and Z
To calculate the distance between X and Z
y^2 = x^2 + z^2 - (2xz)*cosY
x = 20, Z = 10
y^2 = 20^2 + 10^2 - (2*20*10)* cos60°
y^2 = 400 + 100 - (400)* 0.5
y^2 = 500 - 200
y^2 = 300
y = sqrt(300)
y = 17.32m
Bearing of Z from X:
Using cosine rule :
Cos X = (y^2 + z^2 - x^2) / 2yz
Cos X = (300 + 100 - 400) / (2 * 20 '*10)
Cos X = 0 / 400
Cos X = 0
X = cos^-1 (0)
X = 90°
Bearing of Z from X
= 20° + X
= 20° + 90°
= 110°
Hope these help but i wrote all of it out with all its geometrical reasons
