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boyakko [2]
3 years ago
13

D10 (ΔPQR)= (ΔPt Qt Rt), which are the coordinates of P'?

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

You would need transformations to solve this.

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The smallest natural number divisible by 2,3,4,5,6,8 and 9 is____.
SVETLANKA909090 [29]

Answer:

360

Step-by-step explanation:

You will need 2 * 2 * 2 for the smallest number to be divisible by 8 with all the others.

You will need 3 * 3  for the smallest number to be divisible by 9 with all the others.

Finally you will need 1 five

The smallest number divisible by all of these is 2*2*2*3*3*5 = 360

  • 360/2 = 180 works
  • 360/3 = 120 works
  • 360/5 = 72   works
  • 360/6 = 60 works
  • 360/8 = 45 works
  • 360/9 = 40 works.

There is no smaller number below 360 which will work.

7 0
3 years ago
(-9,7), (6,2) write an equation in point-slope form of the line that passes through the given points, then write the equation in
skelet666 [1.2K]

Answer:

y = (2 - 7) / (6 - (-9)) * (x - (-9)) + 7

y = -5 / (6 + 9) * (x + 9) + 7

y = -5 / 15 * (x + 9) + 7

y = -1/3 * (x + 9) + 7

y = -1/3 * x - 3 + 7

y = -1/3 * x + 4

5 0
3 years ago
What is the difference of the expression below? (12f-8g+3h) - (4f - g +5h)
Furkat [3]

<u>Answer: </u>

The difference of (12f - 8g + 3h)  -(4f – g + 5h) is 8f - 7g - 2h

<u>Solution: </u>

From question given that the expression is

(12f - 8g + 3h) - (4f – g + 5h)

We have to find the difference of both the expressions.

By removing the parenthesis the above equation becomes,

12f - 8g + 3h - 4f + g - 5h

Separate the terms of f, g and h in above equation,

12f - 4f - 8g + g + 3h - 5h

On simplifying the above expression,

8f - 7g - 2h

Hence difference of (12f - 8g + 3h) - (4f – g + 5h) is 8f - 7g - 2h  

7 0
3 years ago
PLZ PLZ HELP ME. THANKYOU. WILL GIVE BRAINLIEST
Alex Ar [27]
1. One solution
2.one solution
3.no solution
4.one solution
Hope this helped!
6 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
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