You want to use PEMDAS for this.
<em>P</em>= arenthesis ( )
<em>E</em>= xponents a²
<em>M</em>= ultiply ×
<em>D</em>= ivide ÷
<em>A</em>= dd +
<em>S</em>= ubtract -
What you want to do is go in order and ask yourself as you go.
Are there any <u><em>Parenthesis</em></u>? <em>No
</em>Are there any <u><em>Exponents</em></u><em />? <em>No</em>
Is there any <em /><u><em>Multiplication</em></u><em />? <em>Yes
</em><em />Is there any <em><u>Division</u></em>? <em>No
</em><em />Is there any <em><u>Addition</u></em>? <em>No
</em><em />Is there any <em><u>Subtraction</u></em><u />? <em>Yes</em><em>
</em><em />Thats when you stop and you multiply what you have in the PEMDAS. Top to bottom. 3x5 which gives you 15. Now you equation is 45-15. Thats when you subtract and you get your answer which is 30.
Turn it into y=mx+b form so it is y=2x+2 the b=2 so y intercept is (0,2) and the slope is 2, do a rise of two and a run of 1 and then connect the dots
Answer:
35-5a-3a-12-4=-8a+19
4a-12+7=4a-5
Unequal
Step-by-step explanation:
Answer:
Distance of foot of ladder from building: <em>37.2 inches
</em>
Distance of top of ladder from building's base: <em>114 inches
</em>
Step-by-step explanation:
Please refer to the figure attached in the answer area.
A right angled triangle
is formed by the ladder with the building where hypotenuse is the length of ladder.
Hypotenuse, <em>AC </em>= <em>10 foot
</em>
Also, we are given that angle made by the base of ladder with the ground is
.
We have to find <em>AB</em> and <em>BC</em>.

Using trigonometric functions:


Distance of foot of ladder from building: <em>37.2 inches
</em>
Distance of top of ladder from building's base: <em>114 inches
</em>