Answer:
The distance traveled by the ball is 8.5 m
Explanation:
Initial height of the ball, h₁ = 1.5 m above the ground
final height of the ball, h₂ = 5m
Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m
Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m
Total distance traveled = upward distance + downward distance
Total distance traveled = 3.5 m + 5m = 8.5 m
Therefore, the distance traveled by the ball is 8.5 m
Answer:
d. boost frequencies below 80 Hz.
Explanation:
Low frequency sound appear to be soothing to mind. It is called bass . bass instruments play low frequency notes. But to produce low frequency note , the size of musical instruments have to be increased which increases its cost.
Any instrument which boosts low frequency are therefore costly . They are accompanied by air amplifier.
Answer:
-20°C
Explanation:
The specific heat capacity of ice using the cgs system is 0.5cal/g°C
The enthalpy change is calculated as follows
ΔH=MC∅ where M represents mass C represents specific heat and ∅ represents the temperature change.
10cal = 2g×0.5cal/g°C×∅
∅=10cal/(2g×0.5cal/g°C)
∅=10°C
Final temperature= -30°C+ 10°C= -20°C
Answer:
Explanation:
A )
As the two bicycles come closer , the time period of oscillation of bee to oscillate between the two is gradually reduced . It is akin to a pendulum with gradually decreasing amplitude . It will be infinite number of trips the bee will travel before it gets squished .
B )
The bee will survive until the two bicyclists meet each other .
time of their meeting = distance between them / their relative velocity
= 20 / ( 10 + 10 )
= 1 hour .
C )
Total distance travelled by bee during 1 hour
= time x speed of bee
= 1 x 30 km/h
= 30 km .
In order for the object not to slip, the component of the weight parallel to the surface must be equal to the frictional force (which acts in the opposite direction):
The parallel component of the weight is:
where m is the object mass and
is the angle of the inclined plane.
The frictional force is
where
is the coefficient of static friction.
Equalizing the two forces, we have
from which we find
and so, in our problem the coefficient of static friction must be
