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zvonat [6]
3 years ago
13

Please help me with these two multiple choice questions!

Physics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

11 is A and 12 is C

Explanation:

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Calculate the average net force.
MrRa [10]

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<em>time</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>5</em><em> </em><em>sec</em>

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3 0
3 years ago
A wave is approaching a barrier that has a small hole at the center. Which describes the change in the wave as it encounters the
garri49 [273]

B.The wave will bend or defract

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5 0
3 years ago
Read 2 more answers
when you drop a pebble from height h, it reaches the ground with kinetic energy k if there is no air resistance. from what heigh
marysya [2.9K]

Answer:

From the initial height h

Explanation:

When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already

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3 years ago
What is -37c on the Fahrenheit scale
Arisa [49]
-35 is the ans.wer.hope this hels
8 0
3 years ago
You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb
Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is  I = 15\ kg \frac{m}{s}

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity V_{x} = 20 \frac{m}{s}

Velocity after collision V_{-x} = - 10 \frac{m}{s}

(A). Impulse of the net force on the ball during its collision with wall is

I =  m (V_{x} - V_{-x})

I = 0.5 × (20 + 10)

I = 15\ kg \frac{m}{s}

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

F = \frac{I}{T}

Where F = Force

I = impulse & t = time interval = 0.001 sec

F = \frac{15}{0.001}

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

8 0
3 years ago
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