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Sergio039 [100]
3 years ago
11

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci

ng the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 2.80 m/s, and an 76.6-kg person feels a 341-N force pressing against his back. What is the radius of a chamber?

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:1.76 m

Explanation:

Given

speed of wall=2.8 m/s

mass of person m =76.6 kg

Person feels a force of 341 N

centrifugal force is given by

F_c=\frac{mv^2}{r}

341=\frac{76.6\times 2.8^2}{r}

r=\frac{76.6\times 7.84}{341}

r=1.76 m

Dimas [21]3 years ago
4 0

The radius of a chamber is 1.76 m

\texttt{ }

<h3>Further explanation</h3>

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

<em>a = Centripetal Acceleration ( m/s² )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

<em>F = Centripetal Force ( m/s² )</em>

<em>m = mass of Particle ( kg )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

speed = v = 2.80 m/s

mass of person = m = 76.6 kg

force = F = 341 N

<u>Asked:</u>

radius of chamber = R = ?

<u>Solution:</u>

F = m \frac{v^2}{R}

F \div m = \frac{v^2}{R}

R = mv^2 \div F

R = 76.6 \times 2.80^2 \div 341

\boxed{R \approx 1.76 \texttt{ m}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

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