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lutik1710 [3]
3 years ago
11

The North Colony Trail at Royal Gorge, Colorado, is 18 miles long. Stacey has hiked eight miles to a resting spot. She hikes the

rest of the trail at two miles per hour. When Stacey reached the sixteenth mile, how long has she been walking from the resting spot? Can someone please help I need a good grade please!

Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

4 h

Step-by-step explanation:

The resting spot was at the 8 mi mark.

When Stacey reached the 16th mile, they had covered  

16 mi - 8 mi = 8 mi

They took 2 h for every 1 h, so

\text{Time required} = \text{8 mi} \times \dfrac{\text{1 h}}{\text{2 mi}} = \textbf{4h}

It may be easier to do this calculation on a number line. Each jump of 2 mi represents 1 h, and there are four jumps, so they took four hours.

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mezya [45]

answer:

i got the first two

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3 years ago
Identify the question that is NOT statistical
motikmotik
I’m not sure but I need points
8 0
3 years ago
There are 4 green marbles and 2 red marbles in the jar. You just randomly draw one by one without replacement and stop when you
zalisa [80]

Answer:

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3)  = 2/15

P(4) = 1/15

The expected value for X is:

EV = 1.33...

Step-by-step explanation:

We have a total of 6 marbles in the jar.

The probability of getting a red marble in the first try  (X = 0) is equal to the quotient between the number of red marbles and the total number of marbles, this is:

P(0) = 2/6 = 1/3

The probability of drawing one green marble (X = 1)

is:

First, you draw a green marble with a probability of 4/6

Then you draw the red one, but now there are 5 marbles in the jar (2 red ones and 3 green ones), then the probability is 2/5

The joint probability is:

P(1) = (4/6)*(2/5) = (2/3)*(2/5) = 4/15

The probability of drawing two green marbles (X  = 2)

Again, first we draw a green marble with a probability of 4/6

Now we draw again a green marble, now there are 3 green marbles and 5 total marbles in the jar, so this time the probability is 3/5

Now we draw the red marble (there are 2 red marbles and 4 total marbles in the jar), with a probability of 2/4

The joint probability is:

P(2) = (4/6)*(3/5)*(2/4) = (2/6)*(3/5) = 1/5

The probability of drawing 3 green marbles (X = 3)

At this point you may already understand the pattern:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

finally, we draw a red marble with a probability 2/3

The joint probability is:

P(3) = (4/6)*(3/5)*(2/4)*(2/3) = (2/6)*(3/5)*(2/3) = (1/5)*(2/3) = (2/15)

Finally, the probability of drawing four green marbles (X = 4) is given by:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

fourth, we draw a green marble with a probability 1/3

Finally, we draw a red marble with a probability 2/2 = 1

The joint probability is:

P(4) = (4/6)*(3/5)*(2/4)*(1/3)*1 = (1/5)*(1/3) = 1/15

Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

P(2) = 1/5

P(3)  = 2/15

P(4) = 1/15

The expected value will be:

EV = 0*P(0) + 1*P(1) + 2*P(2) + 3*P(3) + 4*P(4)

EV = 1*(4/15) + 2*( 1/5) + 3*( 2/15) + 4*(1/15 ) = 1.33

So we can expect to draw 1.33 green marbles in this experiment.

5 0
3 years ago
Which multiplication expression is equal to 1/4 divided by 1/3
ioda
Um i think that would probably be something like 2.2
4 0
3 years ago
Read 2 more answers
Need help math problem give you 5 stars and a good rating if you do this
Mazyrski [523]

Answer:

Add 9.6 then divide by 3.2

8 0
3 years ago
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