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Cerrena [4.2K]
3 years ago
9

A bicycle rider increases his speed from 5 m/s to 15 m/s in 10 seconds

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0
To find the acceleration of the bicycle rider, we are going to use the acceleration formula: a= \frac{v_{f}-v_{i}}{t}
where
a is the acceleration 
v_{i} is the initial speed 
v_{f} is the final speed 
t is the time 

We know from our problem that increases his speed from 5 m/s to 15 m/s in 10 seconds, so his initial speed is 5 m/s and his final speed is 15 m/s; therefore, v_{i}=5, v_{f}=15, andt=10. Lets replace those values in our formula:
a= \frac{v_{f}-v_{i}}{t}
a= \frac{15-5}{10}
a= \frac{10}{10}
a=1

We can conclude that the acceleration of the bicycle rider 1 m/s^2
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Answer:

they have different answers

Step-by-step explanation:

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for x- 13 = 4

x=4+13=17

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for 13 - x = 4

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6 0
2 years ago
Evelyn has dance class every Saturday. It lasts 1 hour and 40 minutes and is over at 12:45 P.M.
leva [86]

Answer:

Evelyn's dance class on Saturday starts at 11:05 A.M.

Step-by-step explanation:

I know this because if her class takes an hour and 40 minutes you would subtract the hour and 40 minutes from 12:45 so you could do 12 - 1 which equals 11. Then you would do 45 - 40 which equals 5. And last you would put the new times together so it would be, 11:05. Her dance class starts at 11:05 A.M.

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3 years ago
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Nataliya [291]

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4 0
1 year ago
After heating a fixed volume of gas at 50 psia from 300° R to 600°R, its pressure will be:
Vadim26 [7]

Answer:

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Step-by-step explanation:

Applying,

Pressure law,

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make P' the subject of the equation

P' = PT'/T............ Equation 2

From the question,

Given: P = 50 psia, T = 300°R = (300×5/9)K = 166.66 K, T' = 600°R = (600×5/9)K = 333.33 K

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P' = (50×333.33)/166.66

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4 0
2 years ago
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valentina_108 [34]
7x+8(x+1/4) = 3(6x-9)-8
7x+8x+2      = 18x - 27 -24
15x + 2        =  18x - 51
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          17.66  = x
5 0
3 years ago
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