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horsena [70]
3 years ago
10

Someone help me simplify

Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0
= 14x - 56 - 24x - 6y +8x^2 - 2x + 7y
= 8x^2 - 12x + y - 56
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Which sequence is arithmetic?
MissTica

Answer:

11, 14, 17, 20

Step-by-step explanation:

An arithmetic sequence has a common difference d between consecutive terms.

Consider 2, 6, 18, 54

6 - 2 = 4, 18 - 6 = 12, 54 - 18 = 36 ← no common difference, not arithmetic

Consider 3, 6, 12, 24

6 - 3 = 3, 12 - 6 = 6, 24 - 12 = 12 ← no common difference, not arithmetic

Consider 11, 14, 17, 20

14 - 11 = 3, 17 - 14 = 3, 20 - 17 = 3 ← common difference of 3, so arithmetic

Consider 7, 11, 13, 18

11 - 7 = 4, 13 - 11 = 2, 18 - 13 = 5 ← no common difference, not arithmetic

The arithmetic sequence is 11, 14, 17, 20

3 0
3 years ago
Evalute costheta if sintheta = (sqrt5)/3
torisob [31]

Answer:

\large\boxed{\cos\theta=\pm\dfrac{2}{3}}

Step-by-step explanation:

Use \sin^2x+\cos^2x=1.

We have

\sin\theta=\dfrac{\sqrt5}{3}

Substitute:

\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}

3 0
3 years ago
Read 2 more answers
Write the vertex form of the equation of the parabola that has a vertex of (-6,-5) and passes through the point (-8,6)
Anastaziya [24]

Answer:

Step-by-step explanation:

Find the parabola through  ( − 8 , 6 )  with vertex  ( − 6 , -5 ) .  

Standard Form:  y = − 11 /4x ²− 44 x − 170

Vertex Form:  y = − 11 /4 ( x + 8 ) 2 + 6

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7 0
3 years ago
The sides of a whiteboard are 16 inches by 10 inches. How many 2 inch by 2 inch Post-it notes will be needed to cover the entire
sertanlavr [38]

Answer:

40 Post-it notes

Step-by-step explanation:

10/2 = 5 on the side that measures 10"

16/2 = 8 on the side that measures 16"

5 x 8 = 40 post-it notes

6 0
3 years ago
Read 2 more answers
Given the relation x = y 4 − 9 y 2, identify the x- and y- axis intercepts.
Svetlanka [38]

The x-intercepts are (0,0)

The y-intercepts are (0,0),(0,3),(0,-3)

Explanation:

The relation is x=y^{4} -9y^{2}

To find the x-intercept, let us substitute y=0 in the equation x=y^{4} -9y^{2}, we get,

x=(0)^{4} -9(0)^{2} \\x=0

Thus, the x-intercepts are (0,0)

To find the y-intercept, let us substitute x=0 in the equation x=y^{4} -9y^{2}, we get,

0=y^{4}-9 y^{2}

let us switch sides and solving, we get,

\begin{aligned}y^{4}-9 y^{2} &=0 \\y^{2}\left(y^{2}-9\right) &=0 \\y^{2} &=0, y^{2}-9=0\end{aligned}

Taking square root,

y=0 and \begin{aligned}y^{2}-9 &=0 \\y^{2} &=9 \\y &=\pm 3\end{aligned}

Thus, the y-intercepts are (0,0),(0,3),(0,-3)

5 0
3 years ago
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