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iren2701 [21]
4 years ago
11

K forms the compound K₂O, which is an ionic compound that is brittle. Identify another element, M, that is likely to form a brit

tle, ionic compound with the formula M₂O. Justify your answer in terms of periodic trends.
Chemistry
2 answers:
Lena [83]4 years ago
5 0

Answer:

Na₂O will also form a brittle ionic compound.

Explanation:

Sodium is located in the same group as Potassium: Alkali Metals. This is because both elements have similar chemical properties. In term of their electronegativity, both elements are very close. Na has an electronegativity of 0.93, while K has an electronegativity of 0.82. This makes both ideal elements to create ionic compounds with Oxygen.

notsponge [240]4 years ago
3 0

<u>Answer:</u> The other element is Sodium.

<u>Explanation:</u>

We are given a chemical compound having formula K_2O

The oxidation state of potassium is +1. The group showing oxidation state as +1 is Group 1. Elements belonging to Group 1 are metals.

The oxidation state of elements belonging to same group have same number of valence electrons and thus shows same oxidation state.

Properties shown by metals:

  • They are hard.
  • They are solid at room temperature.
  • They show lustrous property.
  • They are ductile and malleable.

But, there are some exceptions. Sodium and potassium belonging to Group 1 are brittle in nature. They can be easily cut with knife.

The chemical compound having formula M_2O, in which oxidation state of metal is +1 and is brittle in nature.

Hence, the other element will be sodium

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These problems are a bit interesting. :)

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Now to convert to mol of one of our substances we take the percent composition of that particular part of the molecule and multiply it by our starting mass. This is what it looks like using dimensional analyse. 

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Grab a periodic table (or look one up) and find the molar masses for these molecules! Well. In this case I'll do it for you. (Note: I round the molar masses off to two decimal places)

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Now just take the molar mass we found to convert that amount into moles!

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