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3 years ago

List 5 kinds of animals with backbone (Describe each of them)

1 answer:

8 0

Vertebrates are animals with a backbone (think vertebrae). These are the creatures we usually think of when we think of animals. Vertebrates have tremendous diversity in shape, size, ability, and characteristics. They are truly wondrous creatures! The 5 classes of vertebrates are:

Fish, Amphibians, Reptiles, Mammals, and Birds.

All invertebrates obtain food differently, some have a mouth, and others have a beak. The eight different phyla are, Porifera, Cnidarians, Platyhelminthes, Nematoda, Annelida, Echinodermata, Mollusca, and Arthropoda.

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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

3 years ago

Which skeleton equation represents a neutralization reaction? Mg + O2 MgO AlCl3 Al + Cl2 Li + HNO3 H2 + LiNO3 HBr + LiOH LiBr +

creativ13 [48]

Neutralization reaction is the reaction between acid and base.
There the neutralization reaction is:

HBr + LiOH ----------> LiBr + H2O.

Hope this helps!

5 0

3 years ago

Read 2 more answers

H2(g) + Co(g) _CH3OH<br> balance the equation <br>

Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

C: 1a + 0b = 1c

O: 1a + 0b = 1c

H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 1

b = 2

c = 1

4. Substitute Coefficients and Verify Result

CO + 2H2 = CH3OH

L R

C: 1 1 ✔️

O: 1 1 ✔️

H: 4 4 ✔️

8 0

2 years ago

A type of reaction that occurs when oxygen combines with iron to form rust

fiasKO [112]

Oxidation
It is oxidation because two O's 1 x 1 d 2 i's 1 n and 1 a

5 0

3 years ago

Read 2 more answers

What does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide

photoshop1234 [79]

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

3 0

3 years ago