Answer:
New temperature t2 = [1.28T− 273.15]° C
Explanation:
Given:
Volume v1 = 25 gram
New volume v2 = 25 + 7 = 32 gram
Constant pressure = p
Temperature t1 = T
Find:
New temperature t2
Computation:
Pv1/t1 = Pv2/t2
25 / T = 32 / t2
t2 = 1.28T
New temperature t2 = [1.28T− 273.15]° C
Answer:
Ksp = 8.8x10⁻⁵
Explanation:
<em>Full question is:</em>
<em>After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2+ is 2.8 × 10–2 M. What is Ksp for PbCl2?</em>
<em />
When an excess of PbCl₂ is added to water, Pb²⁺ and Cl⁻ ions are produced following Ksp equilibrium:
PbCl₂(s) ⇄ Pb²⁺ + 2Cl⁻
Ksp = [Pb²⁺] [Cl⁻]²
If an excess of PbCl₂ was added, an amount of Pb²⁺ is produced (X) and twice Pb²⁺ is produced as Cl⁻ (2X):
Ksp = [X] [2X]²
Ksp = 4X³
As X is the amount of Pb²⁺ = 2.8x10⁻²M:
Ksp = 4(2.8x10⁻²)³
<h3>Ksp = 8.8x10⁻⁵</h3>
You can Maybe do a volcano?
Answer:
Rock
Explanation:
Let's calculate the density of each object:
Rock:
Pencil:

Therefore the rock is denser.
Answer:
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Explanation:
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