Answer:
The molarity of the new solution is 0.72 M
Explanation:
Step 1: Data given
Volume of the original solution = 360 mL =.360 L
Molarity = 0.87 M
We add 75 mL = 0.075 L
Step 2: Calculate moles
Moles = molarity * volume
Moles = 0.87 M * 0.360 L
Moles = 0.3132 moles
Step 3: Calculate new molarity
The number of moles stays constant
Molarity = moles / volume
Molarity = 0.3132 moles / (0.36+0.075)
Molarity = 0.3132 moles / 0.435 L
Molarity = 0.72 M
The molarity of the new solution is 0.72 M
NH3 +HCl ----> NH4Cl
moles of HCl used = (0.8 x 17.4) /1000= 0.0139 moles
by use of reacting ratio between HCl to NH4Cl which is 1:1 therefore the moles of NH4Cl is also = 0.0139 moles
molar concentration = moles /volume in liters
molar concentration is therefore= (0.0139/5) x1000 = 2.7 M
Answer:
H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)
Explanation:
According to Brönsted-Lowry acid-base theory, an acid is a substance that donates H⁺. Let's consider the molecular equation showing that benzoic acid is a Brönsted-Lowry acid.
C₆H₅COOH(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)
The complete ionic equation includes all the ions and molecular species.
C₆H₅COO⁻(aq) + H⁺(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)
Answer:
Option 6 ) Neutralization
Explanation:
For this case, the missing coefficient would be a "6" before the H₂O, within final products (right side of the equiation), hence, the final reaction should be:
2H₃PO₄ + 3Ba(OH)₂ ------> Ba₃(PO₄)₂ + 6H₂O
You should have in mind that the amount of atoms at each side of the chemical equation should be the same, so as to comply with the principle of mass conservation. If you add "6" on the left side of the H₂O, the equation will be balanced (for each side, lef and right, you will have: 12H, 2P, 14O and 3Ba)
Lastly, this is a chemical neutralization reaction, where an acid (H₃PO₄) is reacting with a base (Ba(OH)₂) in order to finally obtain a neutral salt (Ba₃(PO₄)₂) and water (H₂O)
Answer:
15.17 g
Explanation:
To answer this, we need to find the molar mass of nickel in nickel (II) fluoride. The formula for nickel (II) fluoride is NiF2. This gives us the molar mass of 96.69 g. The mass percentage of nickel is 60.70% approximately (as we divide the molar mass of nickel by that of nickel (II) fluoride), and 60% of 25g gives us 15.17 g
