Answer:
2.73%
Explanation:
Molarity of NaOH = 0.75 M
Density of solution = 1.1 g/mL
Mass percent of NaOH = ?
Solution:
Number of moles of NaOH = 0.75 mol from 0.75 mol/L
Mass of NaOH = number of moles × molar mass
Mass of NaOH = 0.75 mol × 40 g/mol
Mass of NaOH = 30 g
Mass of solution:
d = m/v
1.1 g/ mL = m/ 1000 mL
m = 1100 g
Percentage of NaOH:
% NaOH = mass of solute / mass of solution × 100
% NaOH = 30 g/ 1100 g × 100
% NaOH = 2.73%
Answer : The concentration of 
ion, pH and pOH of solution is, 
, 1.05 and 12.95 respectively.
Explanation : Given,
Concentration of 
ion = 0.090 M
pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.
The expression used for pH is:
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
First we have to calculate the pH.
The pH of the solution is, 1.05
Now we have to calculate the pOH.
The pOH of the solution is, 12.95
Now we have to calculate the concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![12.95=-\log [OH^-]](https://tex.z-dn.net/?f=12.95%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.12\times 10^{-13}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.12%5Ctimes%2010%5E%7B-13%7DM)
The concentration is,
3( 2 carbons + 4 hydrogen's + 2 oxygens)
3*(8) = 24
Answer:
Because the density of water is one
