Answer:
V = 11.21 L
Explanation:
Given data:
Volume of helium = ?
Number of moles = 0.500 mol
Temperature = 273.15 K
Pressure of gas = 1 atm
Solution:
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
V = nRT/P
V = 0.500 mol × 0.0821 atm.L/ mol.K × 273.15 K / 1 atm
V = 11.21 L / 1
V = 11.21 L
Electrons is what defines which element appears in which block.
4KO₂ + 2CO₂ → 2K₂CO₃ + 3 O₂
The two chemicals that have a molar ratio of 3:4 is in equation above O₂ and KO₂
<em><u>explanation</u></em>
The molar ratio is the ratio between the amount in moles of two compounds that are involved in a chemical reaction.
In the equation above the mole ratio is determined by examining coefficient ( <em>number in front of the formula</em>)
the coefficient of O₂ is 3 while that of KO₂ is 4 therefore the mole ratio of O₂:KO₂ is 3:4
