Answer:
Second order
Explanation:
We could obtain the order of reaction by looking at the table very closely.
Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied. So we have;
a situation in which the rate of reaction was tripled;
0.3/0.1 = 2.10/0.699
3^1 = 3^1
Therefore the order of reaction with respect to [S8] is 1.
For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;
x/0.01 = 4.19/2.10
x/0.01 = 2
x = 2 * 0.01
x = 0.02
So we have;
0.02/0.01 = 2^1
2^1 = 2^1
The order of reaction with respect to [OH^-] = 1
So we have the overall rate law as;
Rate = k[S8]^1 [OH^-] ^1
Overall order of reaction = 1 + 1 = 2
Therefore the reaction is second order.
Hey there!:
To find the original sample population density, divide the conted colonies by the dilution factor and the inoculate:
= 73 / (10⁻⁴ * 0.1)
= 73*10⁵
Thus, the original sample's population density was 7.3*10⁶ or 73* 10⁵.
Hope this helps!
Answer:
C6H5COOH + OH- —> C6H5COO- + H2O
Explanation:
C6H5COOH + OH- —> C6H5COO- + H2O
In the reaction above, C6H5COOH donate a proton(H+) to form the carboxylate ion C6H5COO-. The proton (H+) combines with the OH- to form H2O.
This can better be understood in the illustration below
C6H5COOH + NaOH —> C6H5COONa + H2O
Higher probability of loss. Chorionic villus sampling (CVS) and Amniocentesis (AC). The prenatal diagnosis technique can be done earlier in fetal development CVS (first trimester --> 10-13 weeks). AC (second trimester --> 16-20 weeks)
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