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Sidana [21]
3 years ago
13

A solution is composed of 1.15 mL of diethyl ether (C4H10O, density=0.7134 g/mL) dissolved in 78.85 mL of dichloromethane (CH2Cl

2, density=1.3266 g/mL). What is the molarity of the solution?
Chemistry
1 answer:
jeka943 years ago
8 0

Answer:

Molarityof the solution is 0.1375 M.

Explanation:

We will first find the number of moles of diethyl ether (C4H10O)  by finding its molar mass and measured mass.

Molar mass of diethyl ether (C4H10O) = 74.12 g.

Now, volume of diethyl ether (C4H10O) = 1.15 mL and its density = 0.7134 g/mL.

Therefore,  measured mass of diethyl ether (C4H10O) = volume x  density = 1.15 mL x 0.7134 g/mL = 0.82 g.

Now, number of moles of diethyl ether (C4H10O) = \dfrac{Measured \ mass}{ Molar\ mass}= \frac{0.82\ g}{74.12\ g}

= 0.011 Moles.

Volume of the solution = volume of diethyl ether + volume of dichloromethane = 1.15 mL + 78.85 mL = 80 mL.

Now, molarity of the solution = Number of moles of diethyl ether / Volume of the solution( in  mL) x 1000 =  \dfrac {0.011}{80}\times 1000 = 0.1375\ M

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astra-53 [7]

Answer:

A) Q + XZ = X + QZ is a single displacement reaction.

B) Q + Z = QZ is a synthesis reaction

C) QT = Q + T is a decomposition reaction

D) QT + XZ = QZ + XT is double replacement reaction.

Explanation:

A) Q + XZ = X + QZ

This is a single displacement reaction because it is one in which one element is substituted for another one in a compound. In this case X is substituted for Q.

B) Q + Z = QZ

This is a synthesis reaction because Q and z combine to form a single product QZ.

C) QT = Q + T

This is a decomposition reaction because the compound QT breaks down to form 2 simpler substances Q and T.

D) QT + XZ = QZ + XT

Thus is a double replacement reaction because QT and XZ have exchanged cations to form new compounds QZ and XT

6 0
2 years ago
Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C
ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O  (1)  

The enthalpy of reaction (1) is given by:

\Delta H = \Delta H_{r} - \Delta H_{p}   (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

  • 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
  • 7O₂: 7 moles of 1 O=O bond  
  • 4CO₂: 4 moles of 2 C=O bonds  
  • 6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

\Delta H = \Delta H_{r} - \Delta H_{p}

\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})      

\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})  

\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol  

\Delta H = -2860 kJ/mol          

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

Read more here:

brainly.com/question/11753370?referrer=searchResults  

I hope it helps you!        

7 0
3 years ago
If the density of an object is 5.2g/cm3, and it’s volume is 3.7 cm3, what is it’s mass?
lord [1]
Here's the equation you use: Density = mass/volume 

1) 5.2g/cm^3 = m/3.7cm^3 

2) m = 5.2g/cm^3 x 3.7cm^3 

3) m = 19.24g 

You can check the answer by plugging it in 

19.24g/3.7cm^3 
= 5.2g/cm^3
5 0
3 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
Use Avogadro's number, 6.02E23, to calculate the number
Zepler [3.9K]

Answer:

<h2>2.408 × 10²¹ is the correct answer!!</h2>
8 0
3 years ago
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