Answer:
La materia está constituida por átomos, que a su vez forman moléculas. Las moléculas constituyen la mínima parte en la que se puede fragmentar una sustancia para que conserve sus propiedades. Todo lo anterior permite que la materia se pueda presentar en estado sólido, líquido y gaseoso.
Explanation:
The segment of the myocardial conduction framework that has the quickest rate of unconstrained depolarization is the S-A node.Depolarization goes through particular conduction pathways from the S-A hub to the A-V hub. This atrial depolarization happens at a most extreme rate of 0.3 m/sec
Answer:
Cl₂ is the limiting reactant.
Explanation:
- Firstly, we need to write the balanced reaction:
<em>2Na + Cl₂ → 2NaCl,</em>
It is clear that 2 mol of Na react with 1 mol of Cl₂ to produce 2 mol of NaCl.
- Firstly, we need to calculate the no. of moles of 8.0 g Na and 8.0 g Cl₂:
For Na:
n = mass/molar mass = (8.0 g)/(22.989 g/mol) = 0.348 mol.
For Cl₂:
n = mass/molar mass = (8.0 g)/(70.9 g/mol) = 0.113 mol.
- From the stichiometry: 2 mol of Na react with 1 mol of Cl₂ with (2: 1) molar ratio.
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.
So, 0.113 mol of Cl₂ react completely with 0.226 mol of Na which be in excess (0.384 - 0.226 = 0.158 mol).
<em>So, the limiting reactant is Cl₂ which is the reactant has the lowest molar ratio.</em>
Answer:
Your problem is already in standard form.
Explanation:
Unless you wanted coverted to regular notation. Which is 0.0000832.
= 6.022 × 1020
Explanation<em>;</em>
Mole of aluminium oxide (Al2O3) is
⇒ 2 x 27 + 3 x 16
Mole of aluminium oxide = 102 g
i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3
Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)
= 3.011 x 1020 molecules of Al2O3
The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)
= 2 × 3.011 × 1020
=<em> 6.022 × 1020</em>
<em>hope </em><em>it </em><em>helps</em><em>_</em>
