Answer:
0.1066 hours
Explanation:
A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.
t1/2 = ln2/k
t1/2 = ln2/6.5 h⁻¹
t1/2 = 0.1066 h
The half-life of the pesticide is 0.1066 hours.
The negative particles flow or are pushed along a path
D) energy required to remove a valence electron
Explanation:
The ionization energy is the energy required to remove a valence electron from an element.
Different kinds of atoms bind their valence electrons with different amount of energy.
- To remove the electrons, energy must be supplied to the atom.
- The amount of energy required to remove the an electron in the valence shell is the ionization energy or ionization potential.
- The first ionization energy is the energy needed to remove the most loosely bound electron in an atom in the ground state.
- The ionization energy measures the readiness of an atom to loose electrons.
Learn more:
Ionization energy brainly.com/question/5880605
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Frequency = speed of light/ wavelength of photon. wavelength = speed of light/frequency = 3 x 10^8 / 2.43 x 10^8= 1.23m
