Answer:
The pH of the solution will be 3
Explanation:
The strength of acids is determined by their ability to dissociate into ions in aqueous solution. A strong acid is any compound capable of completely and irreversibly releasing protons or hydrogen ions, H⁺. That is, an acid is said to be strong if it is fully dissociated into hydrogen ions and anions in solution.
Being pH=- log [H⁺] or pH= - log [H₃O⁺] and being a strong acid, all the HClO₃ dissociates:
HClO₄ + H₂O → H₃O⁺ + ClO₄-
So: [HCLO₄]= [H₃O⁺]
The molar concentration is:
The molar mass of HClO₄ being 100 g / mole, then if 100 grams of the compound are present in 1 mole, 0.025 grams in how many moles are present?
moles of HClO₄= 0.00025
Then:
![[HClO_{4}]=\frac{0.00025 moles}{0.25 L}](https://tex.z-dn.net/?f=%5BHClO_%7B4%7D%5D%3D%5Cfrac%7B0.00025%20moles%7D%7B0.25%20L%7D)
![[HClO_{4}]=0.001 \frac{ moles}{ L}](https://tex.z-dn.net/?f=%5BHClO_%7B4%7D%5D%3D0.001%20%5Cfrac%7B%20moles%7D%7B%20L%7D)
Being [HCLO₄]= [H₃O⁺]:
pH= - log 0.001
pH= 3
<u><em>The pH of the solution will be 3</em></u>
<u><em></em></u>
Explanation:
Cyclic Hydrocarbons
A cyclic hydrocarbon is a hydrocarbon in which the carbon chain joins to itself in a ring. A cycloalkane is a cyclic hydrocarbon in which all of the carbon-carbon bonds are single bonds. Like other alkanes, cycloalkanes are saturated compounds. Cycloalkanes have the general formula CnH2nCnH2n. The simplest cycloalkane is cyclopropane, a three-carbon ring.
molecules or protein molecules
Answer:
On the basis of your knowledge of the reaction of halogens with alkanes, decide which product you would not expect to be formed in even small quantities in the bromination of ethane?
A) BrCH2CH2Br
B) CH3CH2CH2Br
C) CH3CHBr2
D) CH3CH2CH2CH3
E) BrCH2CH2CH2CH2Br
Explanation:
The reaction of ethane with bromine in presence of UV light forms mono substituted ethane at all primary and secondary carbons.
This is an example of free radical substitution.
The structure of ethane and its bromination is shown below:
Among the given options that which is not possible to form is option B) that is CH3CH2CH2Br(propyl bromide).
Remaining all other products are possisble to form on free radical substitution of ethane.
