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BabaBlast [244]

3 years ago

10

How do you know whether to use mean or median when analyzing a one variable data set (box & whisker plot, histogram)... I lo

oked it up and it said to use median if its skewed right or left and mean if its symmetric, but my math teacher said something else... what do you guys think?

2 answers:

mart [117]3 years ago

4 0

Median is generally good if you have outliers (data points that are very far off from the majority of the points).

Mean can be used otherwise.

AfilCa [17]3 years ago

3 0

Usually, <span>If the data is normally distributed the mean is good to use. If not,
ex( similar distribution), you could use the median.</span>

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A line contains the points (8, 5) and (6, 15).

Olenka [21]

Answer: -5

Step-by-step explanation:

The formula for calculating the slope of a line is given as :

m=\frac{y_{2} }{x_{2}} - \frac{y_{1}}{x_{1}}

$x_{1}$ = 8

$x_{2}$ = 6

$y_{1}$ = 5

$y_{2}$ = 15

substituting into the formula , we have

m = $\frac{15-5}{6-8}$

m = $\frac{10}{-2}$

m = -5

Therefore the slope is -5

3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mashcka [7]

Answer:

Part 1) $-17\frac{8}{9}$ -----> $-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

Part 2) $-15.11$ ------> $-12.48-(-2.99)-5.62$

Part 3) $-19\frac{8}{9}$ -----> $-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

Part 4) $-201.65$ -----> $-353.92-(-283.56)-131.29$

Part 5) $74$ ------> $83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

Step-by-step explanation:

Part 1) we have

$-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

To calculate the subtraction convert the mixed numbers to an improper fractions

$6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}$

$3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}$

$8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}$

substitute

$-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}$

Convert to mixed number

$-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}$

Part 2) we have

$-12.48-(-2.99)-5.62$

To calculate the subtraction eliminate the parenthesis first

$-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11$

Part 3) we have

$-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}$

$4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}$

$3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}$

substitute

$-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})$

Eliminate the parenthesis

$-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}$

Convert to mixed number

$-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}$

Part 4) we have

$-353.92-(-283.56)-131.29$

To calculate the subtraction eliminate the parenthesis first

$-353.92+283.56-131.29=-201.65$

Part 5) we have

$83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}$

$108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}$

$99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}$

substitute

$\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})$

Eliminate the parenthesis

$\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74$

3 0

3 years ago

Can somone give me the answer to 2 x 0

marshall27 [118]

Any number times 0 is going to equal 0

8 0

3 years ago

Read 2 more answers

Match this system of linear equations to the correct description of its solution set.

Misha Larkins [42]

Answer:

Infinite number of solutions.

Step-by-step explanation:

Are the equations written correctly? They are identical. Since they overlap, every point is a solution for as long as the lines reach. Since no one is stopping them, the answers are infinite.

8 0

2 years ago

What is 5 1/2 +2 1/7 due in one hour help please

nika2105 [10]

Answer:

7 9/14

Step-by-step explanation:

1/2=7/14

1/7=2/14

7/14+2/14=9/14

5+2=7

6 0

2 years ago

Read 2 more answers