The center of the atom that contains the proton and the is the

The lightest and heaviest flying birds are the bee hummingbird of Cuba, which weighs about 1.6 grams, and the great bustard of E

VMariaS [17]

Answer:

for the birds to be able to stay vertical in flight without falling down to earth, they must produce a lift that will counteract their weight

for the small bee humming bird,

mass = 1.6 g = 1.6 x $10^{-3}$ kg

weight of the bird under acceleration due to gravity = mg

where g = acceleration due to gravity = 9.81 m/s^2

weight of the bird = 1.6 x $10^{-3}$ x 9.806 = 0.0156 ≅ 0.016 N

for this bird to maintain flight, the least lift upward, it must generate must be equal to its weight downwards, i.e

lift = weight

therefore,

lift = 0.016 N

For the bustard of Europe and Asia,

mass = 21 kg

weight of the bird under acceleration due to gravity = mg

weight of the bird = 21 x 9.806 = 205.9 N

lift = weight = 205.9 N

lift generated is proportional to the wing surface area according to the lift equation

L = Cs x p x $\frac{v}{2}$ x S

where L = lift

C = lift coefficient

p = density of air

v = relative velocity of bird and air

S = surface are of the wing.

The great bustard will have a proportionally larger wing area to hold its weight in flight

7 0

3 years ago

A large box sits on a rough floor. A person pushes on the box with a horizontal force of magnitude 50 N. The box remains at rest

artcher [175]

Answer:

The magnitude of the frictional force is $F_f \ge 50 \ N$

Explanation:

From the question we are told that

The force exerted on the box is $F = 50 \ N$

Generally for the box to remain at rest then it means that the frictional force is greater than or equal to the force applied to move it i.e

$F_f \ge F$

=> $F_f \ge 50 \ N$

5 0

3 years ago

Help ASAP plssssssssss

garik1379 [7]

C. 32400 because 540 * 60 = 32400

5 0

3 years ago

What mass of a material with density rho is required to make a hollow spherical shell having inner radius r1 and outer radius r2

Margarita [4]

Answer:

$m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )$

Explanation:

We have to make a hollow sphere of inner radius $r_1$ and outer radius $r_2$ .

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

$V_t=\frac{4}{3} \pi.r_2^3$

And the volume of the hollow space in the sphere:

$V_h=\frac{4}{3} \pi.r_1^3$

Therefore the net volume of material required to make the sphere:

$V=V_t-V_h$

$V=\frac{4}{3} \pi(r_2^3-r_1^3)$

Now let the density of the of the material be $\rho$ .

Then the mass of the material used is:

$m=\rho.V$

$m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )$

4 0

4 years ago

What did galileo see when he observed venus through his telescope?

nikitadnepr [17]

Galileo saw that Venus went through phases just like the moon .

6 0

3 years ago

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