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3 years ago

13

Which of these statements is always true? Question 12 options: If an object is moving, a net force is acting on it. An object in

equilibrium must not be in motion. A moving object in equilibrium continues at a constant velocity. A moving object in equilibrium can change its direction but not its speed.

1 answer:

Dima020 [189]3 years ago

3 0

A moving object in equilibrium continues at a constant velocity.

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_______ are pictures of relationships.

S_A_V [24]

Answer:

Graphs

Explanation:

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3 years ago

Read 2 more answers

A conductor shaped as a circular loop with a radius of 4.0 m is located in a uniform but changing magnetic field. If the maximum

bekas [8.4K]

Answer:

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

Explanation:

Given that :

The radius of the circular loop = 4.0 m

Maximum Emf $E_{max}$ = 5.0 V

The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;

$E_{max}$ = $Area (A) * \frac{\delta B}{\delta t}$

$E_{max}$ = $\pi r^2 * \frac{\delta B}{\delta t}$

5.0 = $\pi * (4.0)^2 * \frac{\delta B}{\delta t}$

5.0 = $50.27 * \frac{\delta B}{\delta t}$

$\frac{\delta B}{\delta t}= \frac{5}{50.27}$

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

5 0

3 years ago

The acceleration of an object would increase if there was an increase in the

xxMikexx [17]

As per Newton's II law we know that

$F_{net} = ma$

here we know that

$F_{net} = F_{ap} - F_f$

so here we will have

$a = \frac{F_{ap} - F_f}{m}$

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.

So here correct answer will be

<em>A) force on the object.</em>

4 0

4 years ago

Which, at the same temperature, will cool slower on a hot day

kykrilka [37]

The answer would be b.

6 0

3 years ago

If you unbend a paper clip made from 1.5 millimeter diameter wire and push one end against the wall, what force must you apply t

vampirchik [111]

Answer:

The force is $F = 21.48 \ N$

Explanation:

From the question we are told that

The diameter of the wire is $d = 1.5 \ mm = 1.5 *10^{-3} \ m$

The pressure is $P = 120 \ a.t.m = 120 * 101.3 *10^{3} = 12156000 Pa$

Generally the radius of the of the wire is

$r = \frac{d}{2}$

=> $r = \frac{ 1.5 *10^{-3}}{2}$

=> $r = 7.5 *10^{-4} \ m$

The Area is evaluated as

$A = \pi r^2$

=> $A = 3.142 * 7.5 *10^{-4}$

=> $A = 1.7673*10^{-6} \ m^2$

Generally pressure is mathematically represented as

$P = \frac{F}{A }$

=> $F = P* A$

=> $F = 12156000 * 1.767*10^{-6}$

=> $F = 21.48 \ N$

6 0

3 years ago