Answer:
t = 4 s
Explanation:
As we know that the particle A starts from Rest with constant acceleration
So the distance moved by the particle in given time "t"



Now we know that B moves with constant speed so in the same time B will move to another distance

now we know that B is already 349 cm down the track
so if A and B will meet after time "t"
then in that case


on solving above kinematics equation we have

V = p / m
V = 1000 / 2.5
V = 400 m/s
hope this helps!
Answer:
Drag force=1/2Cd*Area*density*V^2
A=240 ft^2
cd=0.75
Drage force=675 lbs
I think you can weigh it 3 and 3.
If they balance, choose set not used.
If not balanced, take the heavier side
then weigh 1 and 1
if balanced, stone not used, if not balanced, take the heavier side
hope this helps