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cluponka [151]
3 years ago
14

Stars that become black holes have more __________ than stars that become neutron stars

Physics
2 answers:
puteri [66]3 years ago
8 0

Answer:

Mass

Explanation:

They have masses ranging from about 5 to several tens of solar masses.

Dominik [7]3 years ago
6 0
I would definitely say mass for sure
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A skier accelerates down the hill at 3m/s2 how fast is he going in 4 seconds​
almond37 [142]

Answer:

Explanation: simple kinematics

we suppose that initially vo= 0 so if the skier moves 4s :

vf = vo +at = 0 + 3*4 = 12 m/s

best wishes from colombia

7 0
3 years ago
Eating eggs for breakfast increases grades. What is the constant?
Feliz [49]

Answer and Explanation:

The answer would be: <u>Breakfast</u>

<u></u>

Breakfast would be the constant of this scenario because this doesn't change. The time of day (for eating eggs) will always be in the morning, so that wouldn't change.

Eating eggs would be the independent variable because you can change this value. This could be a different food or an amount of the food that is being eaten.

The grades would be the dependent variable because the score <em>depends</em> on the eating of eggs.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u></u></em>

<em><u>I hope this helps!</u></em>

6 0
2 years ago
You stand on a frictionless platform that is rotating with an angular speed of 5.1 rev/s. Your arms are outstretched, and you ho
timurjin [86]

Answer:

\omega'=19.419\ rev.s^{-1}

Explanation:

Given:

angular speed of rotation of friction-less platform, \omega=5.1\ rev.s^{-1}

moment of inertia with extended weight, I=9.9\ kg.m^2

moment of inertia with contracted weight, I'=2.6\ kg.m^2

<u>Now we use the law of conservation of angular momentum:</u>

I.\omega=I'.\omega'

9.9\times 5.1=2.6\times \omega'

\omega'=19.419\ rev.s^{-1}

The angular speed becomes faster as the mass is contracted radially near to the axis of rotation.

5 0
3 years ago
A typical cell phone charger is rated to transfer a maximum of 1.0 Coulomb of charge per second. Calculate the maximum number of
Alexandra [31]

Answer:

The maximum no. of electrons- 2.25\times 10^{22}

Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

I = \frac{Q}{t}

Q = ne

where

n = no. of electrons

Q = charge in coulomb

I = current

Thus

Q = It

Thus the charge flow in 1. 0 h:

Q = 1.0\times 3600 = 3600\ C

Maximum number of electrons, n is given by:

n = \frac{Q}{e}

where

e = charge on an electron = 1.6\times 10^{- 19}\ C

Thus

n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}

3 0
3 years ago
9/10 in percents. Examples please, at least 2.
Len [333]

Answer:

90/100%, 9/10%

Explanation:

These represent 9 of 10 parts.

Hope this answer helps you out.

8 0
3 years ago
Read 2 more answers
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