Answer:
![\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Cleft%20%28%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7D%5Ctimes%20mg%7D%20%20%5Cright%20%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Explanation:
Let the length of the string is L.
Let T be the tension in the string.
Resolve the components of T.
As the charge q is in equilibrium.
T Sinθ = Fe ..... (1)
T Cosθ = mg .......(2)
Divide equation (1) by equation (2), we get
tan θ = Fe / mg
![tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B%5Cfrac%7Bkq%5E%7B2%7D%7D%7BAB%5E%7B2%7D%7D%7D%7Bmg%7D)
![tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7DSin%5E%7B%5Ctheta%20%7D%7D%7D%7D%7Bmg%7D)
![tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7DSin%5E%7B2%7D%5Ctheta%20%5Ctimes%20mg%7D)
![tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}](https://tex.z-dn.net/?f=tan%5Ctheta%5Ctimes%20Sin%5E%7B2%7D%5Ctheta%20%3D%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7D%5Ctimes%20mg%7D)
As θ is very small, so tanθ and Sinθ is equal to θ.
![\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}](https://tex.z-dn.net/?f=%5Ctheta%20%5E%7B3%7D%20%3D%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7D%5Ctimes%20mg%7D)
![\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Cleft%20%28%5Cfrac%7Bkq%5E%7B2%7D%7D%7B4L%5E%7B2%7D%5Ctimes%20mg%7D%20%20%5Cright%20%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Answer:
The answer is the 1st one
Answer:
C.As the two objects touch, thermal energy flows as heat from the warmer block to the colder block until particles in both blocks move at the same rate and reach the same temperature.
Explanation:
Heat is the transfer of thermal energy from an object at higher temperature to an object at colder temperature.
The temperature of an object is a measure of how fast the particles in the object move: the higher its temperature, the faster the particles move, the higher the average kinetic energy of the particles in the object. As a result, the particles of the object at higher temperature tend to transfer more energy (called thermal energy) to the particles of the object at colder temperature by colliding with them: this process continues until the particles of the colder object reach the same average kinetic energy as the particles of the warmer object, and this means that the two objects have reached the same temperature.
Answer:
c
Explanation:
it's the only one that makes sense
Answer:
1.3 is equal to m times v to the second times PK, meaning the answer to your question is 3.3 K
Explanation:
Have a gday!