<u>The value of the expression is -35.</u>
<u>Step-by-step explanation:</u>
<u>Consider the provided expression.</u>
<u>3x + y </u>
<u>We need to find the value of the expression for x=13 and y=−74 .</u>
<u>Substitute the value of x=13 and y=−74 in the above expression as shown:</u>
<u>3 (13) + (-74)</u>
<u>39 - 74 </u>
<u>-35</u>
<u> the value of the expression is -35.</u>
Answer:
Purpose!!
Step-by-step explanation:
These are examples of an author's purpose of writing something! :)
You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
There is not a given equation nor ordered pair, so it is impossible to answer this question. I apologise.