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3 years ago

PLEASE ANSWER AS SOON AS POSSIBLE

Mathematics

1 answer:

Hitman42 [59]3 years ago

6 0

4x (4 peaches) = 4y (4.96$)
x (4/4 peaches=1) = y (4.96$ / 4 = 1.24$)
y f(x) = 1.24$

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Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

3 0

3 years ago

Rewrite in simplest terms: -2(5d-9f)+7f-10(-9f-7d)

Afina-wow [57]

Answer:

= 5 ( 12d + 23f )

Step-by-step explanation:

-2(5d-9f)+7f-10(-9f-7d

Open parenthesis

= -10d + 18f + 7f + 90f + 70d

Collect like terms

= -10d + 70d + 18f + 7f + 90f

= 60d + 115f

Factorise

= 5 ( 12d + 23f )

Therefore,

-2(5d-9f)+7f-10(-9f-7d) in its simplest form is 5 ( 12d + 23f )

4 0

2 years ago

Complete the table below to solve the equation $2x + 12 = 4^x$

IrinaVladis [17]

2(2) + 12 = 4^(2)
4 + 12 = 16
16 = 16

only x = 2 will have f(x)=g(x) so x = 2 is answer

5 0

3 years ago

Mark has a jar of marbles. The jar contains 1 red marble, 2 green marbles, 15 yellow marbles, and 11 blue marbles. Without looki

Vitek1552 [10]

Answer:what are that statements

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $1000000 (

aleksandr82 [10.1K]

Answer:

The principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.

Step-by-step explanation:

Given

Accrued Amount A = $1000000

Interest rate r = 6% = 0.06

Time period t = 45 years

Compounded monthly n = 12

To determine:

Principle amount P = ?

Using the formula

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

$P\:=\frac{A}{\left(1\:+\:\frac{r}{n}\right)^{nt}}$

substituting A = 1000000, r = 0.06, t = 45, and n = 12

$P\:=\frac{1000000}{\left(1\:+\:\frac{0.06}{12}\right)^{12\cdot 45}}\:$

$=\frac{1000000}{1.005^{540}}$

$P = 67659.17$ $

Therefore, the principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.

7 0

3 years ago