Answer:
- <u>First choice: 0.042</u>
Explanation:
Given decomposition reaction:
- 1PCl₅ (g) ⇄ 1PCl₃ + 1Cl₂(g)
Equilibrium constant:
Stoichiometric coefficients and powers equal to 1 are not usually shown as they are understood, but I included them in order to shwow you how they intervene in the equilibrium expressions: each concentration is raised to a power equal to the respective stoichiometric coefficient in the equilibrium equation.
So, your calculations are:

<h3>1.<u> Answer;</u></h3>
False
<h3><u>Explanation;</u></h3>
Bases have some of the following properties;
- They have a bitter taste
- They have a slimy, or soapy feel on fingers
- Most bases react with acids and precipitate salts.
- Strong bases may react violently with acids.
- Bases turn red litmus paper blue
<h3>2. <u>Answer;</u></h3>
An acid
<h3><u>Explanation;</u></h3>
- When acids are dissolved in water, the concentration of the acid decreases and it becomes dilute.
- It dissociates in water to give H+ ions or hydrogen ions.
- All acidic solutions contain more hydrogen ions than hydroxide ions, therefore when added to water it increases the concentration of H+ ions in water, as water is a neutral substance whose concentration of H+ ions is equal to OH-.
Answer:
Kc = Kc = 8.0 * 10^9
Kp = 5.5 *10^5
Explanation:
Step 1: Data given
Temperature = 25.0 °C
Number of moles Fe = 1.0 moles
Number of moles O2 = 1.0 * 10^-3 moles
Number of moles Fe2O3 = 2.0 moles
Volume = 2.0 L
Step 2: The balanced equation
4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)
Step 3: Calculate molarity
Molarity = moles / volume
[Fe] = 1.0 moles / 2.0 L
[Fe] = 0.5 M
[O2] = 0.001 moles / 2.0 L
[O2] = 0.0005 M
[Fe2O3] = 2.0 moles / 2.0 L
[Fe2O3] = 1.0 M
Step 4: Calculate Kc
Kc =1/ [O2]³
Kc = 1/0,.000000000125
Kc = 8.0 * 10^9
Step 5: Calculate Kp
Kp = Kc*(R*T)^Δn
⇒with Kc = 8.0*10^9
⇒with R = 0.08206 L*atm /mol*K
⇒with T = 298 K
⇒with Δn = -3
Kp = 8.10^9 *(0.08206 * 298)^-3
Kp = 5.5 *10^5
I think the subatomic particles that are paired with each of their corresponding name would be :
1. X , proton and z, electron
hope this helps