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Law Incorporation [45]
3 years ago
11

What does 2 + 1+ 1 x 10 =

Mathematics
2 answers:
sammy [17]3 years ago
4 0
The answer is 13!

Follow PEMDAS (:
nordsb [41]3 years ago
4 0

Hi,

Answer: 13

<u>My work:</u> Order of operations says that multiplication always goes first so you would start off with 10 * 1. After this you would had 10 with 1 and 2 which equals 13. This problem can be easily solved in 2 steps, or with a caculator.

<u><em>My Numerical work:</em></u>

Multiply first:

1. 10 *1 =10

Add:

2. 10 + 1 + 2 = 13

I Hoped I Helped!


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In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

is obtained by integrating the series above:

f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

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Answer:

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