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Inga [223]
3 years ago
15

Name the values of the given digits in the numbers below 4s in 440

Mathematics
1 answer:
natima [27]3 years ago
6 0
The values given in the number 440:
440-400 (Hundredths)
40-40(Tenths)

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Twice the sum of five and x is eight less than x
Anna007 [38]
We need to express this statement into a equation:

First of all. We will walk through the statement step by step into a mathematical language, so:

1. The sum of five and x:

x + 5

2. Twice the sum of five and x:

2(x + 5)

3. Eight less than x:

(x-8)

     Finally the whole statement is:

4. <span>Twice the sum of five and x is eight less than x:
</span>
2(x + 5) = (x-8)
2x + 10 = x - 8
x = -18


4 0
3 years ago
Simplify 4a​ +​ ​ ​8b ​ -​ ​ ​6b​ +​ ​ 2a​
Deffense [45]
Here is your answer:                                                                                                                              Combine like terms:                                                                                              4a+2a=6a and 8b-6b=2b                                                                                        Your answer is 6a+2b
8 0
3 years ago
Please help me 25 points and the best answer will be marked as brainliest
Zanzabum
May be answer 01
I cant understand the question
7 0
3 years ago
First to answer gets BRAINLEST<br><br> Which graphs show continuous data select all correct answers
solniwko [45]
<h2>Greetings</h2>

Answer:

Graph number 1 and 3

Step-by-step explanation:

This is because continuous data is shown by drawing a line that means the pencil doesn't have to be taken off the page. Seeing as these two graphs are the only two with lines drawn, it means they are graph number 1 and 3.


<h2>Hope this helps!</h2>
6 0
3 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
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