We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
From the question we are told
If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A
Generally the equation for the Concentration Volume relationship is mathematically given as

Therefore
You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
For more information on this visit
brainly.com/question/17756498
https://sciencing.com/make-3d-model-atom-5887341.html
Bicarbonate buffer system in blood consists of carbonic acid and bicarbonate ion. H2CO3/HCO3-
When a base enters the body the acid part of the buffer reacts with the base.
Thats the carbonic acid (H2CO3) reacts with the base.
Answer:
44.2 L
Explanation:
Use Charles Law:

We have all the values except for V₂; this is what we're solving for. Input the values:
- make sure that your temperature is in Kelvin
From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:

Therefore, V₂ = 44.2 L
It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.