Which description of salt is a physical property? (2 points)
1 answer:
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The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Answer:
2.01 M
Explanation:
Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)
The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.
Step 2: Convert the volume of solution to liters
We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)
Step 3: Calculate the molarity of the solution
The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution