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Citrus2011 [14]
3 years ago
5

An average tornado has a pressure of around 630 torr. What is this equivalent to in mmHg, atm and kPa? Show your work.

Chemistry
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

1. 630mmHg

2. 0.83atm

3. 83.99KPa

Explanation:

The pressure obtained from the question is 630 torr.

1. The pressure in mmHg is illustrated below:

760torr = 760mmHg

Therefore, 630torr = 630mmHg

2. The pressure in atm is illustrated below:

760torr = 1atm

630torr = 630/760 = 0.83atm

3. The pressure in kPa is illustrated below:

760torr = 101325Pa

630torr = (630x101325)/760 = 83993.1Pa

But: 1000Pa = 1KPa

83993.1Pa = 83993.1/1000 = 83.99KPa

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