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3 years ago

6

Solve log x = 3. Please help

1 answer:

zhuklara [117]3 years ago

4 0

Answer:

Log x = 3 is the same as Log into base 10 of 3

Recall from Law of Logarithm: if Log a = x , then a = 10^ x

therefore If Log x = 3 , then x = 10^3 = 1000

Step-by-step explanation:

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I need help with finding the equilibrium prices for each one in the table below. I can't seem to understand how to do it. Please

Neporo4naja [7]

Answer:

it might be $0.85 19 i think not 100% sure plz doint report me

Step-by-step explanation:

3 0

3 years ago

What is the volume of the cylinder below?

Anestetic [448]

Volume = πr²h

3.14 * (18 : 2)² * 12 =

3.14 * 9² * 12 =

3.14 * 81 * 12 =

254.34 * 12 =

3052,08 mm³

7 0

3 years ago

Read 2 more answers

In a class of 47 students, the number of males is 7 less than twice the number of females. How many females and how many males a

Rom4ik [11]

X=number of females
47-x=number of males
# of males is 2*(number of females)-7:
47-x= 2x-7
add x to both sides:
47=3x-7
add 7 to both sides:
54=3x
divide both sides by 3:
x= 18 females
47-18= 29 males

6 0

3 years ago

Simplify the following

den301095 [7]

Answer:

1) 11 $\sqrt{3}$

2) 2 $\sqrt{2}$

3) $20\sqrt{3} + 15\sqrt{2}$

4) $53 + 12\sqrt{10}$

5) -2

6) $7\sqrt{2} - 5\sqrt{3}$

Step-by-step explanation:

1) 2 $\sqrt{12}$ + 3 $\sqrt{48}$ - $\sqrt{75}$

=(2 × 2 $\sqrt{3}$ )+ (3 × 4 $\sqrt{3}$ ) - 5 $\sqrt{3}$

= 4 $\sqrt{3}$ + 12 $\sqrt{3}$ - 5 $\sqrt{3}$

= 11 $\sqrt{3}$

2) 4 $\sqrt{8}$ -2 $\sqrt{98}$ + $\sqrt{128}$

= (4 × 2 $\sqrt{2}$ ) - (2 × 7 $\sqrt{2}$ ) + 8 $\sqrt{2}$

= 8 $\sqrt{2}$ - 14 $\sqrt{2}$ +8 $\sqrt{2}$

= 2 $\sqrt{2}$

3) 5 $\sqrt{12\\}$ - 3 $\sqrt{18} + 4 \sqrt{72} +2\sqrt{75}$

= 5× $2\sqrt{3}$ - 3× $3\sqrt{2}$ + 4× $6\sqrt{2}$ + 2× $5\sqrt{3}$

= $10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}$

= $20\sqrt{3} + 15\sqrt{2}$

4) $(2\sqrt{2} + 3\sqrt{5} )^{2}$

= $8 + 12\sqrt{10} + 45$

= $53 + 12\sqrt{10}$

5) $(1+\sqrt{3} ) (1-\sqrt{3} )$

= $1 - 3$

= -2

6) $(2\sqrt{6} -1) (\sqrt{3} -\sqrt{2} )$

= $2\sqrt{18}-2\sqrt{12} -\sqrt{3} +\sqrt{2}$

= 2× $3\sqrt{2}$ - 2× $2\sqrt{3}$ - $\sqrt{3} + \sqrt{2}$

= $6\sqrt{2} - 4\sqrt{3} -\sqrt{3} +\sqrt{2}$

= $7\sqrt{2} - 5\sqrt{3}$

Hope the working out is clear and will help you. :)

5 0

3 years ago

Read 2 more answers

Asap please and thank you

fgiga [73]

Answer:

<h2> x = 16 degrees</h2>

Step-by-step explanation:

1 and 3 are <u>vertical angles</u> so m∠1 = m∠3

(4x - 2)° = 62°

4x - 2 = 62

4x = 64

x = 16

5 0

3 years ago