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Georgia [21]
3 years ago
9

The value of δh° for the reaction below is -482 kj. calculate the heat (kj) released to the surroundings when 24.0 g of co (g) r

eacts completely. 2co (g) + o2 (g) → 2co2 (g)
Chemistry
1 answer:
kiruha [24]3 years ago
8 0

The given thermochemical equation is:

2 CO (g) + O_{2}(g) --->2CO_{2}(g) ΔH^{0} = -482 kJ/mol

Mass of CO given = 24.0 g

Moles of CO = 24.0 g CO * \frac{1 mol CO}{28 g CO} = 0.857 mol CO

Finding out the heat released to the surroundings when 24.0 g CO:

0.857 mol CO * \frac{482 kJ}{2 mol CO} =  207 kJ

Therefore, 207 kJ of heat is released to the surroundings when 24.0 g CO reacts completely.

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What is the empirical formula of propene CH3 CH2 CH2​
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<u>CH</u>

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6 0
2 years ago
A chemist measures the enthalpy change ?H during the following reaction: Fe (s) + 2HCl (g) ? FeCl2 (s) + H2 (g) =?H?157.kJ Use t
erik [133]

Correct Question:

A chemist measures the enthalpy change ΔH during the following reaction: Fe(s) + 2HCl(g)-->FeCl2(s) + H2 ΔH=-157.0 kJ. Use this information to complete the table below. Round each of your answers to the nearest kJ/mol

Answer:

-314 kJ

+628 kJ

+157 kJ

Explanation:

The enthalpy change of a reaction measures the amount of heat that is lost or gained by it. If ΔH >0 the heat is gained, and the reaction is called endothermic, if ΔH<0, the heat is lost, and the reaction is called exothermic.

If the reaction is inverted, the value of ΔH is inverted too (the opposite endothermic reaction is exothermic), and if the reaction is multiplied by a constant, ΔH will be multiplied by it too.

1) 2Fe(s) + 4HCl --> 2FeCl2(s) + 2H2(g)

This reaction is the product of the given reaction by 2, so

ΔH = 2*(-157) = -314 kJ

2) 4FeCl2(s) + 4H2(g) --> 4Fe(s) + 8HCl(g)

This reaction is the inverted reaction given multiplied by 4, so

ΔH = 4*(157) = +628 kJ

3) FeCl2(s) + H2(g) --> Fe(s) + 2HCl

This reaction is the inverted reaction given, so

ΔH = +157 kJ

4 0
3 years ago
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