Answer: A. 1.60 liters
Explanation:
As can be seen from the balanced chemical equation, 2 moles of produce 1 mole of
.
According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.
Thus moles of
occupies
at STP and produce 1 mole of
i.e. 22.4 L
44.8 L of will produce 22.4 L of
Thus of
will produce
Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively
Explanation:
Moles of cyclohexane = 0.069 mole
Volume of solution = 2.8 L
Initial concentration of cyclohexane =
The given balanced equilibrium reaction is,
cyclohexane ⇔ methylcyclopentane
Initial conc. 0.025 M 0
At eqm. conc. (0.025-x)M (x) M
The expression for equilibrium constant for this reaction will be,
K= methylcyclopentane / cyclohexane
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.0027
Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M
Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M
Answer:
The number of moles of KClO₃ reacted was 0,15 mol
Explanation:
For the reaction:
2KClO₃(s) → 2KCl(s) + 2O₂(g)
The only gas product is O₂.
Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:
749mmHg - 23,8mmHg = 725,2mmHg
Using gas law:
PV/RT = n
Where:
P is pressure (725,2mmHg ≡ <em>0,9542atm</em>)
V is volume (<em>5,76L</em>)
R is gas constant (<em>0,082 atmL/molK</em>)
And T is temperature (25°C ≡ <em>298,15K</em>)
Replacing, number of moles of O₂ are <em>0,2248 moles</em>
As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:
0,2248 mol O₂× = <em>0,15 mol of KClO₃</em>
I hope it helps!