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Setler [38]
3 years ago
11

Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr

ed Nobel (1833-1896) founded the Nobel Prizes with a fortune he made by inventing dynamite, a mixture of nitroglycerin and inert ingredients that was safe to handle. 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of liquid nitroglycerin () into gaseous dinitrogen, gaseous dioxygen, gaseous water and gaseous carbon dioxide. 2. Suppose of carbon dioxide gas are produced by this reaction, at a temperature of and pressure of exactly . Calculate the mass of nitroglycerin that must have reacted. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
ELEN [110]3 years ago
6 0

Answer:

4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2

Explanation:

Nitroglycerin has a chemical formula C3H5N3O9. The balanced chemical equation is as follows:

4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2

We suppose that in a reaction, 44g of carbon dioxide is produced. The mass of nitroglycerin that must have reacted will be calculated as under:

Molecular mass of Nitroglycerin = 227g/mol

Molecular mass of Carbon dioxide = 44g/mol

No. of moles of carbon dioxide produced = 44/44 = 1 mole produced.

Now, from balanced chemical equation, we can see that

12 moles of carbon dioxide are produced by = 4 moles of nitroglycerin.

1 mole of carbon dioxide is produced by = 4/12 = 1/3 moles of nitroglycerin.

Mass of nitroglycerin which produced 1 mole of carbon dioxide =  1/3 x 227 = 75.666 grams.

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3 years ago
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. Identify the group 2 metal
andrey2020 [161]

5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.

According to question 5 moles of binary group 2 metal oxide mass =521  g

So, 1-mole metal oxide mass will be =521 / 5=104.2 g

Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1

So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g

Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm

So, the formula of metal oxide is SrO

The group two metal here is Sr which is strontium and lies in the same group as calcium.

To learn more about group 2 metals, visit:

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4 0
2 years ago
The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4
Snowcat [4.5K]

Answer:

a

\Delta H^o _{rxn} = -2568.9 \  kJ

b

H  = 350 JK^{-1}

c

T_{max}  = 32.4 ^o C

Explanation:

From the question we are told that

 The reaction of cyclobutane and oxygen is

         C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

      \Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]

=>  \Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]

=>  \Delta H^o _{rxn} = -2568.9 \  kJ

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is  mathematically represented as

     H  = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]

=>  H  = [ 4 * 37.1 + 6* 33.6 ]

=>   H  = 350 JK^{-1}

From the question the initial temperature of reactant is  T_i  =  25^oC

Generally the enthalpy change(\Delta H^o _{rxn}) of the reaction is mathematically represented as

 |\Delta H^o _{rxn} |=  H  * (T_{max} -T_i)

  2568.9 =   350  * (T_{max} -25)  

=> \frac{2568.9 }{350}  =  T_{max} - 25

=> T_{max}  = 32.4 ^o C

   

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Answer:

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Explanation:

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