C₃H₃O i think. tell me if i’m wrong
the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Molar mass of aluminum = 26.982 g/mol.
1 mol of Al = 26.9≈27g = 6.02×10²³ atoms [ avogadro's number]
meaning
1 g | Al = 6.02/27 × 10²³ atoms
so 3.78g | Al = 6.02×3.78]/27 ×10²³
= 0.8428 ×10²³ atoms
= 8.428 ×10²² atoms