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3 years ago

Which of the following destroys the marine ecosystem?

2 answers:

7 0

C. Dynamite fishing

dynamite fishing is a destructive fishing practice using explosives to stun or kill schools of fish for easy collection. This often illegal practice is extremely destructive to the surrounding ecosystem, as the explosion often destroys the underlying habitat that supports the fish.

Andreyy893 years ago

6 0

Answer:

The correct one is dynamite fishing

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10. The Proton is special! What does it tell us? The proton tells me..

Dovator [93]

Answer:

These two numbers are fixed for an element. The mass number tells us the number the sum of nucleons of protons and neutrons in the nucleus of an atom. The atomic number also known as the proton number is the number of protons found in the nucleus of an atom. ... The atomic number uniquely identifies a chemical element.

Explanation:

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3 years ago

A car traveling with constantspeed travels 150 km in 7200s what is the speed of the car

kompoz [17]

The speed is 7,350km that's the speed of the car

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3 years ago

The majority of Canada’s manufacturing takes place in the provinces of Ontario and __________.

nikklg [1K]

C. Quebec hope this helps :)

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2 years ago

Read 2 more answers

A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema

timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 5.76 L
T1= 22 °C= 295 °K (Being 0°C=273°K)
V2=17.28 L
T2=?

Replacing:

$\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}$

Solving:

$T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}$

T2= 885 °K = 612 °C

The final temperature was 612 °C

5 0

3 years ago

The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the

Ray Of Light [21]

Answer:

$\large \boxed{\text{103 kPa}}$

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

$\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}$

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

$\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}$

3 0

3 years ago