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4 years ago

Please help! Number 8

Mathematics

2 answers:

pochemuha4 years ago

5 0

We know that a straight line is 180 degrees. I'm not sure how to really explain, so bear with me:

We know that 3 in the ratio is 3x 1 in the ratio.

180 divide 3 (parts) = 60

So 3 in the ratio has to be more than 60.

I tried 90.

30 + 90 + 60 = 180

This is the right answer 1/3 of 90 is 30 (1:)

90 is 3/3 (3:)

2/3 of 90 is 60 (3:)

Not really detaild but hopes this helps!

Arlecino [84]4 years ago

4 0

as a fraction of 180, m < 1 = 1/ (1 + 3 + 2) * 180 = 1/6 * 180 = 30 degrees

m < 2 = 3*30 = 90 degrees

and m < 3 = 30*2 = 60 degrees

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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

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3 years ago

A calculator displays a result as 1.3540980 107 kg. the estimated uncertainty in the result is Â±2%. how many digits should be i

yan [13]

<span>2 significant digits.

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In a different plan for area codes, the first digit could be any number from 4 through 8, the second digit was either 3, 4, 5,

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Consider the compound interest equation B(t)=100(1.1664)t. Assume that n=2, and rewrite B(t) in the form B(t)=P(1+rn)nt. What is

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The answer is I think 108

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